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May 27, 2015 at 16:34 answer added R.P. timeline score: 2
May 27, 2015 at 14:38 answer added Ariyan Javanpeykar timeline score: 1
May 27, 2015 at 14:05 comment added naf Consider, for example, a point $p$ on an elliptic curve over $k$. The cohomology class of $[p] - [0]$ is $0$ and some multiple is also $0$, so Galois invariant. However, the cycle itself is Galois invariant iff $p$ is $k$ rational.
May 27, 2015 at 13:45 history edited Joonas Ilmavirta CC BY-SA 3.0
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May 27, 2015 at 13:41 review First posts
May 27, 2015 at 13:45
May 27, 2015 at 13:38 history asked user052715 CC BY-SA 3.0