Skip to main content
9 events
when toggle format what by license comment
Apr 17, 2010 at 9:07 comment added Kaminoite I see.. The problem that I found is that it not assures that $p$ is in the intersection. Nevertheless, as you said, the Baire's theorem asserts that this intersection is dense but, by Borel-Cantelli lemma, that its measure is $0$.
Apr 16, 2010 at 20:19 comment added Ian Morris Oops, I should have said for $\delta$ tending to infinity, not zero. I don't think that there's a problem with Gerald's proof: given any dense orbit $(x_n)$ and real number $\delta>0$, Baire's theorem shows that there exists $p \in \bigcap_{k=1}^\infty \bigcup_{n=k}^\infty B(x_n,e^{-n\delta})$, and by unravelling the meaning of this statement we find that this $p$ satisfies $d(x_n,p)<e^{-n\delta})$ for infinitely many $n$.
Apr 16, 2010 at 17:46 vote accept Kaminoite
Apr 17, 2010 at 9:08
Apr 16, 2010 at 17:46 vote accept Kaminoite
Apr 16, 2010 at 17:46
Apr 16, 2010 at 17:25 comment added Kaminoite Ian, I think that Gerald's proof is not correct? Am I wrong?
Apr 16, 2010 at 16:52 comment added Ian Morris Nice! We could even take a further intersection over a sequence of $\delta$'s tending to zero, proving the existence of points which work simultaneously for all $\delta$.
Apr 8, 2010 at 19:55 comment added Kaminoite This does not mean that $p$ is in the intersection but in its closure.
Apr 8, 2010 at 16:46 history edited Gerald Edgar CC BY-SA 2.5
added 137 characters in body; deleted 2 characters in body
Apr 8, 2010 at 16:40 history answered Gerald Edgar CC BY-SA 2.5