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Nov 17, 2022 at 7:17 comment added JohnAllen aren't you supposed to provide explanation in answers on this site?
May 22, 2015 at 16:08 comment added user9072 @GerhardPaseman Thanks for the summary. He also used the congruence you mentioned.
May 22, 2015 at 16:05 comment added Gerhard Paseman It seems he uses most of the devices David Speyer lists in the posts, plus some other observations about representing $2^{67} -1$ as $((u+v)/2)^2 - ((u-v)/2)^2$. Anyway, he did do some sifting and a lot of modular arithmetic. Gerhard "Maybe It Was A Casio" Paseman, 2015.05.22
May 22, 2015 at 16:04 vote accept David E Speyer
May 22, 2015 at 15:58 history answered user9072 CC BY-SA 3.0