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May 25, 2015 at 7:00 comment added Ural Bekbaev Felipe, your example shows that I can't expect too much from $f(x)$. It seems that I have to reformulate the question in the following form: Under the same conditions can one say that $f(x)$ is algebraic over $F(f_1(x),f_2(x),...,f_n(x))$?
May 24, 2015 at 1:52 vote accept Ural Bekbaev
May 22, 2015 at 19:24 answer added Felipe Voloch timeline score: 4
May 22, 2015 at 19:19 comment added Felipe Voloch @DavidHolmes The question makes sense. Maybe it's clearer to ask whether, given the conditions, there is a rational function $g_1$ satisfying the same hypotheses as $g$.
May 22, 2015 at 8:43 comment added David Holmes Do you mean $g \in F(f_1(x), ... f_n(x))$? Otherwise I don't understand `implies the rationality of $g$'.
May 22, 2015 at 3:53 comment added Włodzimierz Holsztyński The M.A., good job!--you turned a nothing q. title into something sensible.
S May 22, 2015 at 3:50 history suggested The Masked Avenger CC BY-SA 3.0
added a more descriptive title
May 22, 2015 at 3:31 review Suggested edits
S May 22, 2015 at 3:50
May 22, 2015 at 3:01 review First posts
May 22, 2015 at 3:26
May 22, 2015 at 2:59 history asked Ural Bekbaev CC BY-SA 3.0