Timeline for Find the expansion of the exact solution (beyond Taylor)

Current License: CC BY-SA 3.0

13 events

when toggle format	what		by	license	comment
May 21, 2015 at 15:11	answer	added	Brendan McKay		timeline score: 1
May 21, 2015 at 12:25	vote	accept	WoofDoggy
May 21, 2015 at 10:00	comment	added	Carlo Beenakker		@BrendanMcKay --- expanding around the minimum makes sense, but will not give the formula desired by the OP; for that the limit $\mu\rightarrow 0$, $S\rightarrow\infty$ at fixed $\mu^3 S^2$ is needed.
May 21, 2015 at 1:57	comment	added	Brendan McKay		If the point of the exercise was to find the position of the minimum, I'd expand around a point thought to be close to the minimum rather than about 0.
May 20, 2015 at 19:33	answer	added	Carlo Beenakker		timeline score: 2
May 20, 2015 at 16:04	comment	added	WoofDoggy		@CarloBeenakker You mean expanding everything around $\mu=0$ and keep all terms of the order $S\mu$?. In this way I get a polynomial. I am missing something. My idea was to approximate the square root by $A + 2B^2 A/(4A^2+B^2)$.
May 20, 2015 at 15:21	history	edited	WoofDoggy	CC BY-SA 3.0	edited body
May 20, 2015 at 15:21	comment	added	WoofDoggy		Yes, my bad. I have corrected the question.
May 20, 2015 at 13:31	comment	added	Carlo Beenakker		indeed, this is a mistake, S goes to infinity, not to zero, otherwise you cannot have $S\mu$ of order unity and $S\mu^2$ small (in other words, $\mu$ is of order $1/S$).
May 20, 2015 at 13:16	comment	added	Gerald Edgar		@Carlo: He says limit $S \ll 1$ ... so you claim that is a mistake and he intends $S \to \infty$ instead?
May 20, 2015 at 13:15	comment	added	Carlo Beenakker		send $S\rightarrow\infty$, $\mu\rightarrow 0$ at constant $S\mu$.
May 20, 2015 at 12:54	review	First posts
May 20, 2015 at 12:58
May 20, 2015 at 12:53	history	asked	WoofDoggy	CC BY-SA 3.0