Skip to main content
3 events
when toggle format what by license comment
May 19, 2015 at 23:20 comment added Gerry Myerson $a(y,z)=yz-y-z=(y-1)(z-1)-1$, so the only way to get $a(y,z)=1$ is $\{\,y,z\,\}=\{\,2,3\,\}$.
May 19, 2015 at 21:33 history edited Andreas Weingartner CC BY-SA 3.0
added 144 characters in body
May 19, 2015 at 21:20 history answered Andreas Weingartner CC BY-SA 3.0