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S May 19, 2015 at 20:15 history suggested Valborg CC BY-SA 3.0
Added emphasis to the argument that the specific form of the product matters greatly by including a comment about the number of representations of reals of this form.
May 19, 2015 at 19:35 review Suggested edits
S May 19, 2015 at 20:15
May 19, 2015 at 17:20 comment added user13113 For reference, Merten's first theorem says $\sum_{p\leq n} \ln(p)/p = \ln(n) + E_n$ where $|E_n| \leq 2$.
S May 19, 2015 at 17:16 history suggested Valborg CC BY-SA 3.0
Needed to respond to comments, but couldn't make a comment myself. Originally I was unregistered, but now I am.
May 19, 2015 at 16:55 review Suggested edits
S May 19, 2015 at 17:16
May 19, 2015 at 16:47 review Late answers
May 19, 2015 at 17:32
May 19, 2015 at 16:38 comment added Wojowu Could you elaborate on why you think your first claim is true? I guess that you mean to always choose the least $p_i$ such that adding $p_i^{1/e_i}$ factor will make the product not exceed $r$, but I don't see how it guaranteed the product actually converges to $r$ and not something smaller.
May 19, 2015 at 16:32 review First posts
May 19, 2015 at 17:00
May 19, 2015 at 16:29 history answered Valborg CC BY-SA 3.0