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May 19, 2015 at 16:53 comment added Agustín Moreno Oh, ok. That makes more sense... terminology failed me. Sure, if you fix $0$ and $\infty$ to be your branch points, and look at the maps that fix these two points and ramify at them to order 2, then they are of the form $z \mapsto az^2$, which up to reparametrization (i.e dilation) is just the map $z^2$. If you now have two other different ramifying points, take an automorphism mapping them to $0$ and $\infty$, and so, precomposing with it (and a dilation, if necessary) you get the map $z^2$ again. I.e the branch points determine your map up to parametrization, and now I am happy.
May 19, 2015 at 16:06 comment added Chris Gerig The branch points are in the image; it's the critical values that you're really counting.
May 19, 2015 at 9:54 comment added Agustín Moreno Fair enough. But say, why is it true that if you have two maps with different branch points, then they do not differ by an automorphism preserving these points? I want to make sure I am not counting more things...That is what I dont see.
May 18, 2015 at 12:57 history edited Agustín Moreno CC BY-SA 3.0
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May 18, 2015 at 12:15 history answered Agustín Moreno CC BY-SA 3.0