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Jun 7, 2017 at 14:58 vote accept Joseph Van Name
May 5, 2017 at 23:07 answer added Gabe Goldberg timeline score: 7
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S Feb 5, 2017 at 20:48 history bounty started Joseph Van Name
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Feb 4, 2017 at 6:55 comment added Joseph Van Name The I1-tower cardinals also seem to help produce interesting algebras of elementary embeddings. For example, if $A$ is a linear ordering of $V_{\delta}$, then $A$ induces compatible linear orderings on certain finite quotients of algebras of elementary embeddings. Without something like I1-tower cardinals, one has to resort to working within forcing extensions in order to obtain compatible linear orderings.
Jan 28, 2017 at 4:40 history edited Joseph Van Name CC BY-SA 3.0
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May 17, 2015 at 22:53 comment added Joseph Van Name I chose this axiomatization since the I1-tower cardinals are a modification to the notion of a Vopenka cardinal. Recall that a cardinal $\delta$ is a Vopenka cardinal if and only if whenever $A\subseteq V_{\delta}$ there is a $\kappa<\delta$ such that if $\kappa<\alpha<\delta$ there is some elementary embedding $j:\langle V_{\mu},\in,A\cap V_{\mu}\rangle\rightarrow\langle V_{\lambda},\in,A\cap V_{\lambda}\rangle$ with $\lambda,\mu<\delta$,$crit(j)=\kappa$, and $j(\kappa)>\alpha$. Therefore every I1-tower cardinal is a Vopenka cardinal and a limit of I1 cardinals.
May 17, 2015 at 22:52 comment added Joseph Van Name Everett Piper. I simply wanted to extend the notion of an I1 cardinal to a larger cardinal with more consistency strength without resorting to models that necessarily look like L as one has with I0 cardinals, so I want to see what reasonable strengthenings of I1 are possible.
May 17, 2015 at 3:15 comment added Everett Piper @Joseph: Can I ask what the motivation is for this axiom? I think your subsets A cannot contain any member of the critical sequence, or maybe just \kappa, the critical point itself. Maybe there are other subsets that can't be preserved either?
May 16, 2015 at 13:25 comment added Joseph Van Name Victoria. Yes. That is what I meant. Thanks for pointing that out.
May 16, 2015 at 13:24 history edited Joseph Van Name CC BY-SA 3.0
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May 16, 2015 at 13:01 comment added Victoria Gitman Did you mean $A\subseteq V_\delta$ and later $\lambda<\delta$?
May 16, 2015 at 12:52 history asked Joseph Van Name CC BY-SA 3.0