Timeline for about subgroup of general linear group [closed]
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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May 14, 2015 at 7:54 | comment | added | Derek Holt | Yes, as explained in the answer by paul garrett, it is very easy to construct counterexamples. | |
May 14, 2015 at 6:04 | comment | added | maryam | @Professor Holt. Thanks. For other finite fields and other integer $n$, $GL(n,q)$ there exist such a counterexample? | |
May 14, 2015 at 5:55 | comment | added | maryam | @Alex. It is clear that $H_1$ and $h_2$ must be distinct. | |
May 13, 2015 at 23:58 | history | closed |
Alex Degtyarev Derek Holt Stefan Kohl♦ YCor Igor Rivin |
Needs details or clarity | |
May 13, 2015 at 22:35 | answer | added | paul garrett | timeline score: 0 | |
May 13, 2015 at 22:29 | comment | added | Stefan Kohl♦ | I'm voting to close this question because it has been answered in a comment. | |
May 13, 2015 at 22:03 | review | Close votes | |||
May 14, 2015 at 0:02 | |||||
May 13, 2015 at 21:58 | comment | added | Derek Holt | The answer to the question is clearly yes, even if you assume $H_1 \ne H_2$. For example ${\rm GL}(4,2) \cong A_8$ and ${\rm GL}(2,4) \cong A_5 \times C_3$, and there are many possible intersections of pairs of subgroups isomorphic to ${\rm GL}(2,4)$. | |
May 13, 2015 at 21:44 | comment | added | Alex Degtyarev | Where does this question come from? What if $H_1=H_2$? It seems that you assert that any single subgroup with your property is the center. | |
May 13, 2015 at 21:41 | review | First posts | |||
May 13, 2015 at 21:44 | |||||
May 13, 2015 at 21:40 | history | asked | maryam | CC BY-SA 3.0 |