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Apr 13, 2017 at 12:19 history edited CommunityBot
replaced http://math.stackexchange.com/ with https://math.stackexchange.com/
May 12, 2015 at 8:28 comment added YCor That's correct, I'll have to think twice. For the moment it's fine only when $L=F$.
May 12, 2015 at 7:05 comment added Pablo There is an inaccuracy: "By the previous argument on quotients of the infinite symmetric group, we obtain that the action of $\mathrm{Sym}(J)$ on $L/M$ is trivial. " this requires $L/M$ to be finitely generated, which is not a priori clear.
May 11, 2015 at 16:03 history edited YCor CC BY-SA 3.0
replaced particular case with general case
May 11, 2015 at 15:41 history edited Pablo CC BY-SA 3.0
deleted 201 characters in body
May 11, 2015 at 14:05 history answered YCor CC BY-SA 3.0