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Jun 15, 2015 at 11:14 answer added JoS timeline score: 1
May 11, 2015 at 12:43 comment added JoS Thank you very much for your help. If you find a reference please give it as an answer, so I can accept it.
May 11, 2015 at 12:27 comment added Jason Starr I will try to find you a reference. Personally, I would handle it in two steps. First, the induced (1-)morphism from $B$ to the Artin stack $\mathfrak{M}_{0,n}$ of all $n$-pointed, at-worst-nodal curves pulls back the boundary divisor $\Delta$ to be $\underline{0}$, with multiplicity $1$. Second, because of convexity, the $1$-morphism $\overline{M}_{g,n}(X,\beta)\to \mathfrak{M}_{0,n}$ is smooth, so that the pullback of $\Delta$ is a Cartier divisor -- the usual boundary divisor.
May 11, 2015 at 10:28 comment added JoS Ah, ok, but that would be sufficient for me. Do you happen to know a reference for this?
May 11, 2015 at 10:22 comment added Jason Starr For $g=0$, that is sufficient. For larger $g$, it depends on what you mean by "transverse to the boundary" in cases where "the boundary" is not actually a Cartier divisor in the moduli stack.
May 11, 2015 at 10:12 history asked JoS CC BY-SA 3.0