Timeline for When every module is a scalar extension?
Current License: CC BY-SA 3.0
11 events
when toggle format | what | by | license | comment | |
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May 11, 2015 at 12:55 | vote | accept | user237522 | ||
May 11, 2015 at 8:55 | comment | added | Vinteuil | Hochschild, Relative homological algebra, Trans. Amer. Math. Soc. 1956. | |
May 11, 2015 at 8:49 | answer | added | Vinteuil | timeline score: 1 | |
S May 10, 2015 at 19:45 | history | suggested | user 1 |
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May 10, 2015 at 18:51 | review | Suggested edits | |||
S May 10, 2015 at 19:45 | |||||
S May 10, 2015 at 18:44 | history | suggested | Rahman. M |
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May 10, 2015 at 18:25 | review | Suggested edits | |||
S May 10, 2015 at 18:44 | |||||
May 10, 2015 at 18:08 | comment | added | user237522 | Thank you both. Please can you recommend books/papers dealing with relative free modules? | |
May 10, 2015 at 17:04 | comment | added | grghxy | @JohannesHahn: what do you mean by "more or less equivalent"? If $B$ is a nonzero ring that is not a field and $I$ is a maximal ideal of $B$ then $B/I$ is a $B$-module that is not free. | |
May 10, 2015 at 16:58 | comment | added | Johannes Hahn | A module of the form $M\otimes B$ is sometimes called "relative free" (and a direct summand of such a module is called "relative projective"). You're asking for coniditions when every module is relative free. If $A$ is a field, then this means that every $B$-module is free which is more or less equivalent to being a principle ideal domain. | |
May 10, 2015 at 16:49 | history | asked | user237522 | CC BY-SA 3.0 |