Skip to main content
5 events
when toggle format what by license comment
May 8, 2015 at 21:58 comment added Đức Anh Thank you all very much. I have thought too complicatedly.
May 8, 2015 at 21:55 comment added Deane Yang Probably the easiest way to figure this out is to write out the second order expansion of each function.
May 8, 2015 at 21:41 comment added Christian Remling Yes, you're right of course, this needs to be done more carefully. You could try to write $e^{\psi}\simeq e^{\psi_0+t\psi'}$ and use Campbell-Hausdorff now.
May 8, 2015 at 21:29 comment added Đức Anh Thank you, but I worry about the derivative of $e^{\psi}$ because of non-commutativity between $\psi'$ and $\psi$ (therefore I think we may not have an explicit formula for $(e^{\psi})'$)
May 8, 2015 at 21:16 history asked Đức Anh CC BY-SA 3.0