Timeline for Derivative of a conjugation of matrices
Current License: CC BY-SA 3.0
5 events
when toggle format | what | by | license | comment | |
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May 8, 2015 at 21:58 | comment | added | Đức Anh | Thank you all very much. I have thought too complicatedly. | |
May 8, 2015 at 21:55 | comment | added | Deane Yang | Probably the easiest way to figure this out is to write out the second order expansion of each function. | |
May 8, 2015 at 21:41 | comment | added | Christian Remling | Yes, you're right of course, this needs to be done more carefully. You could try to write $e^{\psi}\simeq e^{\psi_0+t\psi'}$ and use Campbell-Hausdorff now. | |
May 8, 2015 at 21:29 | comment | added | Đức Anh | Thank you, but I worry about the derivative of $e^{\psi}$ because of non-commutativity between $\psi'$ and $\psi$ (therefore I think we may not have an explicit formula for $(e^{\psi})'$) | |
May 8, 2015 at 21:16 | history | asked | Đức Anh | CC BY-SA 3.0 |