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Oct 25, 2009 at 21:47 history edited Ilya Nikokoshev CC BY-SA 2.5
strike out wrong part
Oct 11, 2009 at 21:12 comment added Ilya Nikokoshev Ok, it's certainly my mistake --- I basically thought det exp A is defined as exp tr A which would make (1) trivial. But for the reference, I think books.google.com/… might help.
Oct 8, 2009 at 22:01 comment added Ilya Nikokoshev I'll return to this on the weekend and see if I'm right :).
Oct 8, 2009 at 20:38 comment added Theo Johnson-Freyd Great, although any chance you can either spell out the reasoning or point me to a reference? For example, here's what I know about (1). Let A have eigenvalues A_n. Then DET exp A is: compute \sum A_n \exp(-s A_n), extend, and evaluate at s=0. exp TR A is: compute \exp( \sum A_n^{-s}), extend, and evaluate at s=-1. Is there a change of variables to get from one of these functions to the other? Otherwise, I don't know why their extensions should match up. But perhaps I'm being dumb.
Oct 8, 2009 at 20:26 history answered Ilya Nikokoshev CC BY-SA 2.5