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Sep 20, 2021 at 14:24 vote accept Roland Bacher
Jul 27, 2015 at 19:03 comment added Steven Stadnicki @DylanThurston You're probably already aware, but the decision problem is trivial; any two simple of the same area are, of course, scissors-congruent. Computing the area takes time linear in the number of vertices and I believe that confirming simplicity is $O(n\log n)$ at worst.
May 28, 2015 at 11:12 answer added Igor Pak timeline score: 2
May 7, 2015 at 8:43 comment added Dylan Thurston I'm not sure how to clarify it, but when I first read the title I thought you were asking about the computational complexity of deciding whether or not there is a scissors congruence.
May 7, 2015 at 7:43 history asked Roland Bacher CC BY-SA 3.0