Timeline for A Question about Palindromic Numbers and System of Arithmetic Progression
Current License: CC BY-SA 3.0
21 events
| when toggle format | what | by | license | comment | |
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| S May 15, 2015 at 21:51 | history | bounty ended | Jr Antalan | ||
| S May 15, 2015 at 21:51 | history | notice removed | Jr Antalan | ||
| May 15, 2015 at 2:00 | vote | accept | Jr Antalan | ||
| May 14, 2015 at 23:17 | answer | added | Terry Tao | timeline score: 11 | |
| May 14, 2015 at 17:15 | history | edited | Bjørn Kjos-Hanssen | CC BY-SA 3.0 |
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| May 11, 2015 at 12:34 | comment | added | Jr Antalan | Can I also post this in mathematics stack exchange? Thanks a lot. | |
| May 8, 2015 at 20:08 | comment | added | Jr Antalan | That is true @JohnBinder. Those cases are exceptions. | |
| May 8, 2015 at 16:00 | comment | added | John Binder | Just a trivial point; usually numbers ending in $0$ are not counted as palendromes. So if one of your sequences is $10*t$ for instance you are out of luck. Perhaps you want to make clear that you're excluding such cases or else allow $1100$ to be a palendrome as $001100$. | |
| S May 8, 2015 at 15:49 | history | bounty started | Jr Antalan | ||
| S May 8, 2015 at 15:49 | history | notice added | Jr Antalan | Authoritative reference needed | |
| May 7, 2015 at 23:34 | comment | added | Jr Antalan | Thanks @GerhardPaseman will try to do that. Thanks again. But if ever you have the result, kindly inform me Sir. | |
| May 7, 2015 at 23:14 | comment | added | Gerhard Paseman | The idea is to choose m and n (and r) and consider the arithmetic progression (10^n+1)(pt+j) + (10^m +10^r)(qt+k). Although it won't be a palindrome for some choices of m and r and n, there is a lot of room to play in, and perhaps you can find ranges of t that guide your choice of m,n and r. If so, you have reduced two progressions to one, hopefully making it easier to study and predict. Gerhard "Maybe Consider Several Choices Simultaneously" Paseman, 2015.05.07 | |
| May 6, 2015 at 21:35 | comment | added | Jr Antalan | Thanks @GerhardPaseman, sorry if I am having a hard time on understanding your comment, In particular what does $m$ represent and what is the meaning of combining the two system. As well as pt+j...qt+k...qt+k...pt+j. I am hopeful that with your help I can understand the answer to my query. Thanks again. | |
| May 6, 2015 at 18:28 | comment | added | Gerhard Paseman | Consider combining the systems into one. For n large and t small, pt + j is a palindrome implies (10^n + 1)(pt+j) is a palindrome. Consider how small t can be for both expressions to be palindromic, then pick n and m very large and with the right parity and consider pt+j ... qt+k ... qt+k ... pt+j. You can write this as a single recurrence that hopefully will produce a palindrome for some t depending on m and n. Gerhard "Give Yourself Plenty Of Room" Paseman, 2015.05.06 | |
| S May 6, 2015 at 14:50 | history | suggested | CommunityBot | CC BY-SA 3.0 |
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| May 6, 2015 at 14:33 | review | Suggested edits | |||
| S May 6, 2015 at 14:50 | |||||
| May 6, 2015 at 12:36 | comment | added | Jr Antalan | Yes Sir @GerryMyerson, it must be that p and q are relatively prime. | |
| May 6, 2015 at 12:35 | comment | added | Gerry Myerson | You certainly need some restrictions. $3t+1$ and $3t+2$ can't both be palindromes (unless you allow single digit numbers). Ah, I posted this before you edited in the gcd condition. | |
| May 6, 2015 at 12:35 | history | edited | Jr Antalan | CC BY-SA 3.0 |
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| May 6, 2015 at 12:27 | review | First posts | |||
| May 6, 2015 at 12:36 | |||||
| May 6, 2015 at 12:26 | history | asked | Jr Antalan | CC BY-SA 3.0 |