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May 12, 2015 at 15:48 comment added user 1 Fernando Muro is right, but this answer is helpful.
May 2, 2015 at 15:17 comment added John Palmieri Fred: It could be in this case, though. Take a graded free resolution of $R/I$; this is still free in the ungraded case. I think the only issue is that there will be extra ungraded maps from a graded free module to $R$. I wonder if those can be dealt with in some nice way.
May 2, 2015 at 15:11 comment added John Palmieri Fernando: you're right, I was misinterpreting the question as asking whether Ext^i was zero for positive i.
May 1, 2015 at 5:18 comment added Fred Rohrer Graded Ext is not necessarily the same as ungraded Ext!
Apr 30, 2015 at 23:10 comment added Fernando Muro I don't think he or she wants to put a grading on R. Actually, direct computation shows that the answer is no since there are no module maps from the quotient to the ring.
Apr 30, 2015 at 18:13 history answered John Palmieri CC BY-SA 3.0