Timeline for Constant rank theorem for Banach spaces
Current License: CC BY-SA 4.0
14 events
| when toggle format | what | by | license | comment | |
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| Mar 24 at 22:09 | history | edited | LSpice | CC BY-SA 4.0 |
Capitalise title, while this is on the front page
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| Feb 15, 2020 at 16:57 | answer | added | Daniel Luckhardt | timeline score: 3 | |
| May 6, 2015 at 6:45 | comment | added | Jochen Wengenroth | @TomekKania You are of course right. Replying to Benjamin's comment I though of Hilbert spaces. | |
| May 5, 2015 at 20:00 | comment | added | Tomasz Kania | Yes, I meant Schauder basis too. | |
| May 5, 2015 at 19:37 | comment | added | Benjamin | I really only meant separability, a Schauder basis was the basis to which I was referring. I don't think the existence of a Hamel basis will affect my application, but we'll see. | |
| May 5, 2015 at 19:34 | comment | added | Tomasz Kania | @Jochen Wengenroth, a separable Banach space need not have a basis so strictly speaking these two things are not equivalent :-) | |
| May 5, 2015 at 19:21 | answer | added | Alexander Schmeding | timeline score: 3 | |
| May 5, 2015 at 14:17 | comment | added | Benjamin | Ok, that's clear and you are of course correct, thanks. | |
| May 5, 2015 at 7:34 | comment | added | Jochen Wengenroth | I meant no countable Hamel basis, of course you can have a countable Schauder basis. I believe, that "x-dimensional" usually refers to Hamel bases. Having a countable Schauder basis is equivalent to separability. | |
| May 4, 2015 at 14:53 | comment | added | Benjamin | What about separable Hilbert spaces? | |
| May 4, 2015 at 6:58 | comment | added | Jochen Wengenroth | There are no countable dimensional Banach spaces. | |
| Apr 30, 2015 at 19:05 | vote | accept | Benjamin | ||
| Apr 30, 2015 at 18:16 | answer | added | Pedro Lauridsen Ribeiro | timeline score: 7 | |
| Apr 30, 2015 at 17:38 | history | asked | Benjamin | CC BY-SA 3.0 |