Timeline for Is the set $ AA+A $ always at least as large as $ A+A $?
Current License: CC BY-SA 3.0
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| Apr 27, 2015 at 14:07 | review | Low quality posts | |||
| Apr 27, 2015 at 14:13 | |||||
| Apr 27, 2015 at 14:04 | comment | added | j.p. | Yes, I was referring with "size" (implicitly) to the number of elements in the discrete case. | |
| Apr 27, 2015 at 14:01 | comment | added | Gerald Edgar | @j.p.: we are using real numbers, so $1/2$ can be an element of $A$. But you are right we would want $AA$ not merely to be half the size, but rather to have half the number of elements. | |
| Apr 27, 2015 at 13:57 | comment | added | j.p. | With measures you can make sets "smaller" by multiplying its element with a number $<1$. $AA$ becomes scaled smaller twice. This doesn't happen in the discrete case. | |
| Apr 27, 2015 at 13:47 | history | answered | Gerald Edgar | CC BY-SA 3.0 |