Skip to main content
10 events
when toggle format what by license comment
Dec 21, 2016 at 15:17 comment added Will Sawin @DominiqueUnruh Well, one should read what I wrote in context. The reason the oracle problem is relevant here is that, if Craig Feinstein's strategy works for factoring, it necessarily works for the oracle problem as well.
Dec 21, 2016 at 12:43 comment added Dominique Unruh @WillSawin True, if the function is given as an oracle, abelian hidden subgroup is provably hard. If the function is given as a circuit (or in any other white-box way), then it abelian HSG might be easy (e.g., if P=NP). If abelian HSG is given an oracle, but the oracle is required to be implemented by a poly-time algorithm -- then I don't know. So I guess your statement is right depending on the interpretation, but I still feel that it's good that we have this comment threat to point out that it's not all clear black-and-white. :)
Dec 20, 2016 at 12:10 comment added Will Sawin @DominiqueUnruh It is not proven for real-world problems but it is known for oracle problemss. The abelian hidden subgroup problem is an oracle problem, which unless I am very confused has no fast classical algorithm for the reason I described.
Dec 20, 2016 at 10:03 comment added Dominique Unruh "But there is no fast classical algorithm for the abelian hidden subgroup problem" -- I think you should phrase this "no fast classical algorithm is known". Although it is commonly believed that quantum computers are more powerful than classical ones, this is not proven.
Apr 27, 2015 at 0:50 vote accept Craig Feinstein
Apr 27, 2015 at 0:49 vote accept Craig Feinstein
Apr 27, 2015 at 0:49
Apr 27, 2015 at 0:49 comment added Craig Feinstein I think you are correct, @willsawin.
Apr 26, 2015 at 18:40 comment added Will Sawin @CraigFeinstein Yes, the classical steps of the computation are permutation matrices, which are not problematic. What I mean by "just the Fourier transform" is that the only thing we do to the sequence $x^a$ mod $n$ is compute it and then apply the Fourier transform. We don't investigate its properties using deep number theory technology.
Apr 26, 2015 at 18:04 comment added Craig Feinstein I don't follow your reasoning. Shor's algorithm doesn't just take the Fourier Transform. It computes $x^a (\bmod n)$ too. But the unitary matrices associated with these computations do not appear to be problematic, as they are just permutation matrices, right?
Apr 26, 2015 at 15:39 history answered Will Sawin CC BY-SA 3.0