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S Mar 27, 2023 at 18:40 history suggested Steven Clontz CC BY-SA 4.0
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Mar 27, 2023 at 18:07 review Suggested edits
S Mar 27, 2023 at 18:40
Apr 26, 2015 at 20:39 comment added Mirko @Corbennick My counterexample no longer works as the answerer corrected condition 2, replacing countable union with disjoint union.
Apr 26, 2015 at 20:11 history edited Joseph Van Name CC BY-SA 3.0
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Apr 26, 2015 at 13:50 comment added user1688 Here is a proof that 3 implies 1: Let $(V_i)$ be any open covering and $(U_j)$ a locally finite one by relatively compacts. Then each $U_j$ can be covered by finetely many $V_i$. Replace each $U_j$ by the finietely many intersections with those $V_i$ and you found a locally finite refinement of $(V_i)$.
Apr 26, 2015 at 13:45 comment added user1688 I agree that 1 and 3 are equivalent, but condition 2 is out of place here as Mirko gave a counterexample.
Apr 25, 2015 at 21:48 history edited Joseph Van Name CC BY-SA 3.0
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Apr 25, 2015 at 20:45 history answered Joseph Van Name CC BY-SA 3.0