Skip to main content
8 events
when toggle format what by license comment
Apr 26, 2015 at 8:36 vote accept Ron
Apr 25, 2015 at 15:43 answer added Will Sawin timeline score: 4
Apr 24, 2015 at 18:45 comment added Ron You can take the base to be $\mathrm{Spec} R$ for a complete DVR $R$.
Apr 24, 2015 at 18:24 comment added Kestutis Cesnavicius But saying "projective space" without specifying the base doesn't make sense either.
Apr 24, 2015 at 16:30 history edited Ron CC BY-SA 3.0
edited title
Apr 24, 2015 at 15:52 comment added Ron A standard use of the term "Projective scheme" is to mean a closed subscheme of a projective space. Here the morphisms are implicit, not necessary for the problem.
Apr 24, 2015 at 15:42 comment added Kestutis Cesnavicius Projective is a property of a morphism, not of a scheme, so it doesn't make sense to say that $X$ and $Y$ are projective without specifying the base.
Apr 24, 2015 at 14:02 history asked Ron CC BY-SA 3.0