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Dec 3, 2021 at 4:35 comment added brainjam @MikeShulman, the synthetic approach to the complex plane was popular back in the day. There are lots of accounts, e.g. Hatton, Imaginary Geometry.
Apr 27, 2015 at 7:54 comment added Francesco Polizzi Uhm, not that I'm aware of. But I'm not really an expert of synthetic projective geometry.
Apr 27, 2015 at 7:14 comment added Mike Shulman Fraser's paper opens with a sketch of what appears to be a synthetic construction of the complex projective plane from the real one (I'm not sure what it would be in the general case, maybe the closure of a field under square roots?). This looks very cool, but there are a lot of details left out; is it written down carefully anywhere?
Apr 24, 2015 at 18:44 vote accept Mike Shulman
Apr 24, 2015 at 18:44 comment added Mike Shulman Fraser's paper seems to be exactly what I was looking for, thanks! (It's actually easier for me to read than your description, since I'm not an algebraic geometer but I've read some synthetic projective geometry.)
Apr 22, 2015 at 8:36 comment added Francesco Polizzi I'm assuming that the ground field is any algebraically closed field $k$ of characteristic $0$ (for instance $k= \mathbb{C})$. The chapter on curves in Hartshorne's book is a good introduction for all this stuff.
Apr 22, 2015 at 8:35 history edited Francesco Polizzi CC BY-SA 3.0
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Apr 22, 2015 at 8:30 comment added Francesco Polizzi It is a $1$-dimensional linear system of degree $2$ over a curve. By Riemann-Roch, since a smooth plane curve has genus $1$, every effective divisor of degree $2$ defines a $g^1_2$ on it. The classical term for such a object was "rational involution": in fact, every $g^1_2$ determines uniquely a degree $2$ morphism $C \to \mathbb{P}^1$.
Apr 22, 2015 at 8:09 comment added Dima Pasechnik @MikeShulman - this is some particular kind of divisor, IIRC...
Apr 22, 2015 at 7:36 comment added Mike Shulman What is a $g^1_2$?
Apr 22, 2015 at 6:43 history answered Francesco Polizzi CC BY-SA 3.0