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Apr 29, 2015 at 3:10 answer added user3700540 timeline score: 1
Apr 13, 2015 at 21:12 comment added Christian Remling These things usually boil down to exercises in (symplectic) linear algebra. The operator will be self-adjoint precisely if it is symmetric and a restriction of the maximal operator of the right dimension, as indicated by the deficiency indices.
Apr 13, 2015 at 20:19 review First posts
Apr 13, 2015 at 20:20
Apr 13, 2015 at 20:15 history asked Janu CC BY-SA 3.0