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Apr 15, 2015 at 11:25 vote accept coudy
Apr 14, 2015 at 18:38 comment added Arno @TonyK While being positive is not decidable, it is semidecidable. So we try for all rationals within the current bounds to find a proof that the function is positive/negative there. If the function is not constant 0, we'll find one eventually, and replace the appropriate current interval bound with it.
Apr 14, 2015 at 18:31 comment added TonyK @Arno: How can we compute such an interval, when we can't even decide whether a computable number is positive or negative?
Apr 14, 2015 at 17:32 comment added Arno @TonyK: Using a modified bisection algorithm, we can compute an interval (as a closed set, ie approximated from the outside) on which the function is zero. Now comes the non-constructive case distinction: If the interval contains a single point, we can compute this. If not, it contains some rational (and rationals are computable).
Apr 14, 2015 at 15:54 comment added TonyK "Any computable function [...] has a computable root": I'm surprised by that. I'm pretty sure that not every such computable function has a constructively computable root.
Apr 14, 2015 at 0:28 comment added Arno Yes, Orevkov was first. Baigger's work is built on Orevkov's construction and filling in some more details.
Apr 14, 2015 at 0:20 comment added Timothy Chow Was Baigger the first? I thought it was Orevkov in 1963?
Apr 13, 2015 at 19:56 history answered Arno CC BY-SA 3.0