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Dec 1 at 6:11 comment added Maxim Leyenson You would only get the primes dividing the conductor, not the conductor itself...
Apr 1, 2010 at 21:53 comment added Soroosh Regarding N being the smallest N that keeps track of the degeneracy locus, won't that calculate the radical of the discriminant? That seems different from the conductor, which distinguishes between places of additive reduction and places of multiplicative reduction. I think the correct way of approaching this is to think of conductor as a representation theory invariant, while the natural geometric invariant is the discriminant. These two however are related via Ogg's formula (or I guess Ogg-Saito's formula).
Oct 23, 2009 at 4:02 history edited Ilya Nikokoshev CC BY-SA 2.5
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Oct 23, 2009 at 3:39 history answered Ilya Nikokoshev CC BY-SA 2.5