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Dec 12, 2023 at 2:02 comment added David Feldman No, a cubic surface need not be singular at an Eckardt point. Look here for example: blogs.ams.org/visualinsight/2016/02/15/… A double line would make the surface singular though.
Dec 11, 2023 at 5:15 history edited David Feldman CC BY-SA 4.0
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Dec 11, 2023 at 5:08 history edited David Feldman CC BY-SA 4.0
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Nov 26, 2016 at 12:12 comment added Andrea Ferretti Yes, but the point is singular then
Nov 26, 2016 at 9:52 comment added Daniel Loughran Unfortunately you proof is not correct. Three lines on a cubic surface can indeed meet in one point; this is a so-called "Eckardt point".
Nov 27, 2010 at 4:49 comment added roy smith the existence of a line argument is in Shafarevich, Basic algebraic geometry chapter one, and the discriminant quintic argument is detailed in Beauville's Complex algebraic surfaces, both in English. But I welcome the translation of the other notes as well.
Apr 4, 2010 at 13:35 comment added Andrea Ferretti Glielo suggerirò volentieri la prossima volta che lo incontro!
Apr 4, 2010 at 12:54 comment added Georges Elencwajg Sono interessanti e ben scritti questi appunti di Manetti. Se conosce questo Professore, forse pottrebbe suggerirgli di tradurli in inglese e di pubblicarli. Comprerei volentieri un tal libro!
Apr 3, 2010 at 20:56 history edited Andrea Ferretti CC BY-SA 2.5
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Apr 3, 2010 at 20:47 comment added Andrea Ferretti If you actually choose this topic, you may want the details of the computations I have skipped (although you can find them yourself). The only reference I know on this proof is the book "Geometria algebrica" by Marco Manetti, which you can find here: mat.uniroma1.it/people/manetti/dispense/dispense.html Unfortunately it is in italian, but the few parts you need should be understandable. You find the proof on page 221.
Apr 3, 2010 at 20:26 history answered Andrea Ferretti CC BY-SA 2.5