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S Jun 13, 2017 at 6:59 history suggested Topological
Cohomology instead of etale cohomology
Jun 13, 2017 at 5:36 review Suggested edits
S Jun 13, 2017 at 6:59
S Apr 14, 2017 at 13:07 history suggested Ascenso
Added Grothendieck topology tag
Apr 14, 2017 at 12:37 review Suggested edits
S Apr 14, 2017 at 13:07
Sep 28, 2012 at 23:22 vote accept Sam Derbyshire
Sep 26, 2012 at 11:01 answer added Thomas Geisser timeline score: 19
Mar 26, 2012 at 23:03 comment added Keenan Kidwell Regarding the vanishing of higher direct images, it tells you that the Leray spectral sequence degenerates into a family of isomorphisms $H^p(X_{Zar},f_*(\mathcal{F}))\rightarrow H^p(X_{et},F)$.
Apr 3, 2010 at 23:42 comment added BCnrd A concrete way to see the vanishing for the qcoh case is Cartan's criterion for vanishing of higher sheaf cohomology (in terms of Cech-like cohomologies, applied in the etale topology) and the use of a cofinal system of affine etale covers of an affine scheme, coupled with the exactness of the long Cech-like complex built for a module and a faithfully flat ring extension (which in turn rests on the essential content of Grothendieck's brilliant trick with a section to prove fpqc descent for qcoh sheaves).
Apr 3, 2010 at 22:00 history edited Sam Derbyshire CC BY-SA 2.5
Added a comment about the second question, following Scott's comment.
Apr 3, 2010 at 19:17 history edited Sam Derbyshire CC BY-SA 2.5
Changed wording for necessity of R^qf_* being 0
Apr 3, 2010 at 19:08 history edited Sam Derbyshire CC BY-SA 2.5
Added an example of failure
Apr 3, 2010 at 18:57 history edited Sam Derbyshire CC BY-SA 2.5
Explained the little understanding I have of the proof in SGA 4
Apr 3, 2010 at 18:50 comment added S. Carnahan Regarding your subquestion, the restriction functor $\epsilon: X_{\'et} \to X_{Zar}$ has a right adjoint $\epsilon^{-1}$, and it returns the sheaf associated to the presheaf $(U,f) \mapsto \mathcal{G}(f(U))$. You have to take a tensor product to get the $\mathcal{O}$-module functor $\epsilon^*$, and this turns out to be an equivalence on quasicoherent modules.
Apr 3, 2010 at 18:09 history asked Sam Derbyshire CC BY-SA 2.5