Timeline for Norm of a matrix operator with a special structure
Current License: CC BY-SA 3.0
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| Apr 8, 2015 at 11:28 | comment | added | Miel Sharf | Not really, but here is what I would try to do - look at operators of the same shape on finite dimensional spaces. You know that the operator norm there is just the highest singular value, so (hopefully) you can compute it. Now, the operator norm of the original operator is a supermum on all sequences in $\ell^2$ of some expression, which is the same as the supermum of the same expression on eventually zero sequences. For those, you already have the expression for the operator norm by the above calculation. | |
| Apr 8, 2015 at 10:09 | comment | added | Twi | Thanks. Any idea for the norm $\|C\|$ in the case when $C$ is bounded? | |
| Apr 8, 2015 at 7:52 | history | edited | Miel Sharf | CC BY-SA 3.0 |
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| Apr 7, 2015 at 21:01 | history | answered | Miel Sharf | CC BY-SA 3.0 |