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Apr 7, 2015 at 4:31 comment added Fan Zheng I'm not sure what approximation you're talking about. Presumably there's no such approximation in Gilbarg-Trudinger.
Apr 7, 2015 at 4:02 comment added 张德凯 I know that $\int_{(Du-\varepsilon I)(\Omega)}{g(p)}dp= \int_{\Gamma^{+}}{g(Du-\varepsilon I)|\det (D^2u-\varepsilon I)|}dx$. But I don't know how to use approximation.
Apr 5, 2015 at 19:35 history answered Fan Zheng CC BY-SA 3.0