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Removed loops, e.g., 50+50.
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Joseph O'Rourke
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(Not an answer; just a comment.)

It is a somewhat tangled graph. Here is a representation of $G(100)$:


          ![SqGraph100][1]
One can see $50+50=100=10^2$ at$50+71=121=11^2$ near the lower-right corner, $69+52=121=11^2$$84+85=169=13^2$ near the upper-right cornertop, $70+51=121=11^2$$82+62=144=12^2$, left midlevelnear the bottom, etc.

This $G(100)$ graph has diameter $5$. But $G(1000)$ has diameter $4$.

(Not an answer; just a comment.)

It is a somewhat tangled graph. Here is a representation of $G(100)$:


          ![SqGraph100][1]
One can see $50+50=100=10^2$ at the lower-right corner, $69+52=121=11^2$ near the upper-right corner, $70+51=121=11^2$, left midlevel, etc.

This $G(100)$ graph has diameter $5$. But $G(1000)$ has diameter $4$.

(Not an answer; just a comment.)

It is a somewhat tangled graph. Here is a representation of $G(100)$:


          ![SqGraph100][1]
One can see $50+71=121=11^2$ near the lower-right corner, $84+85=169=13^2$ near the top, $82+62=144=12^2$, near the bottom, etc.

This $G(100)$ graph has diameter $5$. But $G(1000)$ has diameter $4$.

Corrected 69+52 sum (as suggested by joro in a comment)
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Benjamin Dickman
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(Not an answer; just a comment.)

It is a somewhat tangled graph. Here is a representation of $G(100)$:


          ![SqGraph100][1]
One can see $50+50=100=10^2$ at the lower-right corner, $69+52=111=11^2$$69+52=121=11^2$ near the upper-right corner, $70+51=121=11^2$, left midlevel, etc.

This $G(100)$ graph has diameter $5$. But $G(1000)$ has diameter $4$.

(Not an answer; just a comment.)

It is a somewhat tangled graph. Here is a representation of $G(100)$:


          ![SqGraph100][1]
One can see $50+50=100=10^2$ at the lower-right corner, $69+52=111=11^2$ near the upper-right corner, $70+51=121=11^2$, left midlevel, etc.

This $G(100)$ graph has diameter $5$. But $G(1000)$ has diameter $4$.

(Not an answer; just a comment.)

It is a somewhat tangled graph. Here is a representation of $G(100)$:


          ![SqGraph100][1]
One can see $50+50=100=10^2$ at the lower-right corner, $69+52=121=11^2$ near the upper-right corner, $70+51=121=11^2$, left midlevel, etc.

This $G(100)$ graph has diameter $5$. But $G(1000)$ has diameter $4$.

Source Link
Joseph O'Rourke
  • 150.9k
  • 36
  • 358
  • 958

(Not an answer; just a comment.)

It is a somewhat tangled graph. Here is a representation of $G(100)$:


          ![SqGraph100][1]
One can see $50+50=100=10^2$ at the lower-right corner, $69+52=111=11^2$ near the upper-right corner, $70+51=121=11^2$, left midlevel, etc.

This $G(100)$ graph has diameter $5$. But $G(1000)$ has diameter $4$.