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Dec 19, 2015 at 18:37 history edited user9072
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Apr 3, 2015 at 23:39 vote accept Giulio
Apr 3, 2015 at 19:55 answer added Eric Wofsey timeline score: 21
Apr 3, 2015 at 19:52 comment added Giulio So also T2 and connected is not enough; mine seems a hopeless question
Apr 3, 2015 at 19:51 history edited Giulio CC BY-SA 3.0
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Apr 3, 2015 at 19:46 comment added Qiaochu Yuan Yes, that's what I mean. Similarly, for $\mathbb{R}$ take the closed intervals $[-n, n]$.
Apr 3, 2015 at 19:41 comment added Giulio @QiaochuYuan Do you mean that if we take $X_n$ to be the set $\{1,\dots, n\}$ with the disccret topology and as maps the inclusions, then the limit is $\mathbb{N}$, which is not compact?
Apr 3, 2015 at 19:39 history edited Giulio CC BY-SA 3.0
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Apr 3, 2015 at 19:31 comment added Qiaochu Yuan Rarely? I mean, $\mathbb{N}$ is a filtered colimit of compact spaces, and so is $\mathbb{R}$. Can you be more specific about what you're looking for?
Apr 3, 2015 at 19:26 history asked Giulio CC BY-SA 3.0