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Gerry Myerson
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Is it possible to find 23 consecutive positive integers each of which has mutually distinct exponents in its canonical prime factorization? Such numbers are sequence A130091A130091 in OEIS. 24 such numbers are impossible because of 36n-6$36n-6$ and 36n+6$36n+6$.

Is it possible to find 23 consecutive positive integers each of which has mutually distinct exponents in its canonical prime factorization? Such numbers are sequence A130091 in OEIS. 24 such numbers are impossible because of 36n-6 and 36n+6.

Is it possible to find 23 consecutive positive integers each of which has mutually distinct exponents in its canonical prime factorization? Such numbers are sequence A130091 in OEIS. 24 such numbers are impossible because of $36n-6$ and $36n+6$.

Grammar again!
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Consecutive numbers with mutually distinct exponents in itstheir canonical prime factorization

Missing letter: 36n+6
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I improved grammar and statement to avoid ambiguity.
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