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Apr 1, 2015 at 19:19 answer added Sent from my iphone timeline score: -1
S Mar 30, 2015 at 19:02 history suggested Robert A. Neiss CC BY-SA 3.0
Restrict $a$ to roots of unity.
Mar 30, 2015 at 18:55 review Suggested edits
S Mar 30, 2015 at 19:02
S Mar 30, 2015 at 18:46 history suggested Robert A. Neiss CC BY-SA 3.0
Restrict $a$ to roots of unity.
Mar 30, 2015 at 18:36 review Suggested edits
S Mar 30, 2015 at 18:46
Mar 30, 2015 at 15:32 comment added David Loeffler (PS: I suspect this isn't an answer to the question you meant to ask, so can you refine the question to rule out such silliness?)
Mar 30, 2015 at 15:30 comment added David Loeffler You want this to be impossible for $a \in \mathbf{C}^*$ and $|a| < 1/4$, with no other conditions on $a$? Then you're out of luck. Let $\rho$ be a rational number a tiny little bit bigger than 1/2 (but smaller than $\sqrt{1/4 + 1/4^m}$). Then there's a unique real algebraic number $a \in (0, 1/4)$ such that $\sqrt{1/4 + a^m} = \rho$, and for this $a$ the condition that $\sqrt{1/4 + a^m} \in \mathbf{Q}(\zeta_m, a)$ is vacuously satisfied because $\rho \in \mathbf{Q}$.
Mar 30, 2015 at 14:00 review First posts
Mar 30, 2015 at 14:03
Mar 30, 2015 at 13:59 history asked Robert A. Neiss CC BY-SA 3.0