Timeline for A problem with pointwise stabilizer subgroups of fixed-point subspaces II
Current License: CC BY-SA 3.0
10 events
when toggle format | what | by | license | comment | |
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Apr 1, 2015 at 14:50 | history | edited | Sebastien Palcoux | CC BY-SA 3.0 |
remove wrong check
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Apr 1, 2015 at 13:17 | history | edited | Sebastien Palcoux | CC BY-SA 3.0 |
the program for checking was incorrect, now it's much more long in time, i've improved the check data
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Apr 1, 2015 at 4:14 | history | edited | Sebastien Palcoux | CC BY-SA 3.0 |
proof "could" be generalized assuming U^H, V^H non-zero.
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Mar 31, 2015 at 15:25 | history | edited | Sebastien Palcoux | CC BY-SA 3.0 |
improvment of the last remark
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Mar 31, 2015 at 9:59 | history | edited | Sebastien Palcoux | CC BY-SA 3.0 |
remark on the general case.
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Mar 29, 2015 at 6:50 | comment | added | Sebastien Palcoux | @MartyIsaacs: You're right, for $u,v≠0$, $g(u⊗v)=u⊗v$ iff $gu=αu$ and $gv=βv$ with $αβ=1$. Now, we can replace this equality by an inclusion and the argument still works. I've edited that, thank you! | |
Mar 29, 2015 at 3:17 | history | edited | Sebastien Palcoux | CC BY-SA 3.0 |
the first equality was replaced by an inclusion.
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Mar 28, 2015 at 17:35 | comment | added | Marty Isaacs | It seems that the first equality in the lemma of Palcoux is not true in general. The kernel of the tensor product of two modules is not necessarily the intersection of the kernels. For example, look at G the Klein four's group. The tensor product of two distinct nontrivial irreducible representations is the third one, and its kernel is nontrivial. | |
Mar 28, 2015 at 5:47 | history | edited | Sebastien Palcoux | CC BY-SA 3.0 |
notation
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Mar 28, 2015 at 5:23 | history | answered | Sebastien Palcoux | CC BY-SA 3.0 |