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Timeline for Problems concerning R and R[x]

Current License: CC BY-SA 2.5

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Apr 2, 2010 at 3:20 comment added S. Carnahan ...assuming $0 \neq 1$ :)
Apr 2, 2010 at 1:19 comment added Keenan Kidwell Another really easy way to see that $R[X]$ fails to be Artin is the descending chain $(X)\supseteq (X^2)\supseteq\cdots$.
Apr 2, 2010 at 1:16 history edited Keenan Kidwell CC BY-SA 2.5
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Apr 2, 2010 at 1:11 history answered Keenan Kidwell CC BY-SA 2.5