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Mar 25, 2015 at 20:05 comment added Bjørn Kjos-Hanssen Yes, although there may be other sufficient conditions @StevenPav
Mar 25, 2015 at 19:01 comment added Steven Pav This kind of kicks the can down the road: the question becomes, "are there sufficient conditions for stochastic dominance on $\mathcal{X}$ to be a total ordering?"
Mar 25, 2015 at 17:44 history edited Bjørn Kjos-Hanssen CC BY-SA 3.0
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Mar 25, 2015 at 16:50 comment added Steven Pav I think you need a $\le$ at the split of your equations.
Mar 25, 2015 at 5:51 history edited Bjørn Kjos-Hanssen CC BY-SA 3.0
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Mar 25, 2015 at 5:21 history answered Bjørn Kjos-Hanssen CC BY-SA 3.0