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Apr 1, 2015 at 12:08 vote accept CommunityBot
Mar 24, 2015 at 17:37 history edited JoS CC BY-SA 3.0
Expanded by a proof of the desired property of ev when restricted to an open set of the target
Mar 24, 2015 at 17:21 comment added JoS So I think that surjectivity is not enough: if you look at the case $n=2, d=1, N=2$ then $ev$ is surjective as through any two points $p,q$ in $\mathbb{P}^2$ there is a line. If $(p,q)$ is not in the diagonal, there is exactly one such line, so the fibre of $ev$ is a point, for $p=q$ however the fibre is positive-dimensional (elements are in correspondence with lines through $p=q$). Hence $ev$ is not flat as fibre dimension jumps. However, I think that over a dense open subset of the target, $ev$ has the desired property. I will try to edit my answer accordingly.
Mar 24, 2015 at 15:44 comment added user58604 Thanks al lot. From your argument it seems that if $ev:=ev_1\times ...\times ev_n$ is surjective then the push-forward of the structure sheaf is the structure sheaf. Am I rigth?
Mar 24, 2015 at 12:33 review First posts
Mar 24, 2015 at 12:36
Mar 24, 2015 at 12:28 history answered JoS CC BY-SA 3.0