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Mar 24, 2015 at 21:14 history edited Fedor Petrov CC BY-SA 3.0
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Mar 24, 2015 at 20:52 comment added Sasha Do you mean "isomorphic to $\pi$"?
Mar 24, 2015 at 15:28 answer added Hari Krovi timeline score: 2
Mar 24, 2015 at 12:18 comment added Geoff Robinson By the way, the $2$-dimensional irreducible representation of $S_{4}$ is "really" a representation of $S_{3}$, because it has the normal Klein $4$-subgroup of $S_{4}$ in its kernel.
Mar 24, 2015 at 12:15 answer added Geoff Robinson timeline score: 4
Mar 24, 2015 at 7:23 vote accept Fedor Petrov
Mar 24, 2015 at 6:54 answer added Amritanshu Prasad timeline score: 8
Mar 24, 2015 at 6:17 history asked Fedor Petrov CC BY-SA 3.0