Timeline for If a polynomial $p(z)$ omits a value, then $p(z)-\dfrac{(1-e^{i\psi})}{n}zp^{\prime}(z)$ also omits that value

13 events

when toggle format	what		by	license	comment
Mar 24, 2015 at 0:57	answer	added	Christian Remling		timeline score: 5
Mar 24, 2015 at 0:44	history	reopened	Yemon Choi Paul Taylor Christian Remling Lucia Todd Trimble
Mar 23, 2015 at 18:48	history	edited	Christian Remling	CC BY-SA 3.0	added 10 characters in body; edited title
Mar 23, 2015 at 15:14	history	edited	Suhail	CC BY-SA 3.0	added 401 characters in body
Mar 23, 2015 at 13:36	review	Reopen votes
Mar 23, 2015 at 14:53
Mar 23, 2015 at 13:23	comment	added	Suhail		@ Alexandre: There was a typo error in expression $p(z)-\dfrac{(1-e^{i\psi})}{n}zp^{\prime}(z).$
Mar 23, 2015 at 13:20	history	edited	Suhail	CC BY-SA 3.0	edited body; edited title
Mar 23, 2015 at 9:17	history	closed	Alexandre Eremenko abx Joonas Ilmavirta Dima Pasechnik Stefan Kohl♦		Needs details or clarity
Mar 23, 2015 at 5:41	comment	added	Feldmann Denis		<strike>Huh? What is the value omited by $p(z)=z$ ?</strike> Sorry, I had only read the title
Mar 23, 2015 at 3:24	review	Close votes
Mar 23, 2015 at 9:17
Mar 23, 2015 at 3:07	comment	added	Alexandre Eremenko		This is not true: take p(z)=z$, $\psi=\pi$, $w=1$.
Mar 23, 2015 at 2:59	review	First posts
Mar 23, 2015 at 5:16
Mar 23, 2015 at 2:56	history	asked	Suhail	CC BY-SA 3.0