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Apr 13, 2017 at 12:19 history edited CommunityBot
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Apr 11, 2015 at 13:10 history edited Alecos Papadopoulos CC BY-SA 3.0
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Mar 22, 2015 at 21:40 comment added user47855 Thank you again, I didn't understand the parameter of differentiation, now I agree.
Mar 22, 2015 at 15:55 comment added Alecos Papadopoulos @user47855 Yes, because $\phi()'$ is the derivative with respect to the argument shown, i.e with respect to $\beta$ and $\alpha$. But we are considering the derivatives with respect to $\mu$. So we need to take into account also $\partial \beta /\partial \mu = \partial \alpha /\partial \mu =-1/\sigma$. Start with the first derivative of $\ln H$ and you will arrive there.
Mar 22, 2015 at 11:56 comment added user47855 Alecos, thank you for such a detailed answer! Are you sure $ D $ has this form and not $ [ \phi'(\alpha) - \phi'(\beta) ] \ldots $?
Mar 21, 2015 at 18:52 review First posts
Mar 21, 2015 at 19:10
Mar 21, 2015 at 18:51 history answered Alecos Papadopoulos CC BY-SA 3.0