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Mar 20, 2015 at 20:53 history edited Vladimir S Matveev CC BY-SA 3.0
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Mar 20, 2015 at 11:15 vote accept Bilateral
Mar 20, 2015 at 10:06 comment added Vladimir S Matveev It depends of course what you understand by compatible. It is parallel, and the corresponding endomorphism is a complex structure, though not the standard one. Alternatively, you make take another symplectic form $-dx_1\wedge dy_1+ dx_2\wedge dx_2$; it corresponds to the standard complex structure
Mar 19, 2015 at 22:38 comment added Bilateral thanks for the example. Do you know of any pseudo-Kahler example? If I am not mistaken, in your example the symplectic form that you use is compatible with the Riemannian metric, not the (2,2) metric.
Mar 19, 2015 at 22:15 history answered Vladimir S Matveev CC BY-SA 3.0