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May 18, 2016 at 18:34 history edited Andy Putman CC BY-SA 3.0
Fix broken link
Mar 19, 2015 at 16:05 comment added Andy Putman @MarkGrant : It's definitely true if $|G|$ is invertible in $F$ (with the same proof). As for whether the isomorphisms respect cup products, I rather doubt it, though I don't have an example in mind. If $G$ acts freely (so the projection $M \rightarrow M/G$ is a covering map), then the isomorphism is induced by the transfer map. See the answer to mathoverflow.net/questions/58159/… for an example of where this is not a ring homomorphism (though that example is not over a field of characteristic $0$).
Mar 19, 2015 at 7:54 comment added Mark Grant Presumably this can be promoted to a statement about graded algebras? And is it also true if $|G|$ is invertible in $F$?
Mar 19, 2015 at 2:43 vote accept Shiquan Ren
Mar 19, 2015 at 1:52 history answered Andy Putman CC BY-SA 3.0