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Mar 19, 2015 at 18:50 comment added Gustavo Sorry, my mistake, this is true for every group G, like Primoz just said. The assumptions are needed for it to say that $\pi_3 SX \cong ker(\kappa)$ for a space $X$, where $\kappa : \pi_1 X \otimes \pi_1 X \to (\pi_1 X)'$ is the commutator epimorphism. These are: $X$ is path-connected and $\pi_2 X = 0$. Then you can see that the above follows.
Mar 18, 2015 at 9:13 comment added Primoz This is true for every G; see R. Brown, J.-L. Loday, Van Kampen theorems for diagrams of spaces, Topology 26 (1987), 311--335.
Mar 18, 2015 at 5:22 comment added Joonas Ilmavirta What are these assumptions? Or can you give at least examples to make it more concrete?
Mar 18, 2015 at 4:37 review Late answers
Mar 18, 2015 at 5:22
Mar 18, 2015 at 4:27 review First posts
Mar 18, 2015 at 4:51
Mar 18, 2015 at 4:22 history answered Gustavo CC BY-SA 3.0