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Mar 21, 2015 at 15:02 vote accept TMM
Mar 19, 2015 at 23:57 history edited Brendan McKay CC BY-SA 3.0
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Mar 19, 2015 at 23:55 comment added Brendan McKay Since I was assuming $p\le\frac12$, the largest value of the fourth derivative of $f$ in the interval $[\frac p2,1-\frac p2]$ occurs at $x=\frac p2$. And the fourth derivative is positive in the interval. I used that in the standard formula for the remainder term.
Mar 19, 2015 at 12:18 comment added TMM Thanks for the answer. How exactly did you get the expressions for $f_j(x)$? What bound on the remainder term did you use there?
Mar 18, 2015 at 2:54 history edited Brendan McKay CC BY-SA 3.0
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Mar 18, 2015 at 1:42 history edited Brendan McKay CC BY-SA 3.0
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Mar 18, 2015 at 1:23 history edited Brendan McKay CC BY-SA 3.0
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Mar 18, 2015 at 0:33 history answered Brendan McKay CC BY-SA 3.0