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Mar 17, 2015 at 19:09 vote accept math-Student
Mar 17, 2015 at 18:51 vote accept math-Student
Mar 17, 2015 at 18:51
Mar 17, 2015 at 7:50 comment added Jochen Wengenroth By "over a finite product" you probably mean "with values in"?
Mar 17, 2015 at 5:09 answer added Anthony Quas timeline score: 3
Mar 17, 2015 at 3:11 comment added Suvrit I asked, because it is not clear from the outset, where would the fact that $T$ is a conditional expectation operator play a role for monotonicity --- it seems to be used mostly for the contractivity. On the other hand, even non-contractive operators can lead to a monotonic ratio, so maybe your hypothesis does play a role...
Mar 17, 2015 at 2:53 comment added math-Student @suvrit, I focus only on conditional expectation operator. For arbitrary contractive operator, I guess, the monotonicity breaks.
Mar 17, 2015 at 1:16 comment added Suvrit Does this monotonicity break for an arbitrary contractive operator?
Mar 16, 2015 at 22:31 history asked math-Student CC BY-SA 3.0