Timeline for Does there exist a fibre bundle $K(\mathbb{Z}_4,1)\rightarrow K(\mathbb{Z}_2,1)$ with fiber $K(\mathbb{Z}_2,1)$?
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Apr 13, 2017 at 12:19 | history | edited | CommunityBot |
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Mar 16, 2015 at 2:16 | comment | added | ThiKu | If you want a locally trivial fibre bundle, then you should say so in your question. A fibration (in the sense of Serre or Hurewicz) is a considerably weaker notion. In particular, path spaces are fibrations but (I think) not necessarily fibre bundles. | |
Mar 15, 2015 at 20:23 | comment | added | Samarkand | Thanks Tom. I was thinking about constructing explicit locally trivial bundle, I did not mention it in the question though. | |
Mar 15, 2015 at 20:04 | history | answered | Tom Church | CC BY-SA 3.0 |