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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Mar 15, 2015 at 20:27 comment added YCor If you have a finite 2-group $G$, then the set of automorphisms acting as the identity on $G/G^2$ is a normal 2-subgroup, and the quotient is a subgroup of automorphisms of $G/G^2$ which should be computable with not too much effort in your case.
Mar 15, 2015 at 19:32 comment added Igor Rivin @GeoffRobinson Well, for the source question, it would be good to get enough information to find the automorphism group...
Mar 15, 2015 at 19:30 answer added Jeff Yelton timeline score: 5
Mar 15, 2015 at 18:34 comment added Geoff Robinson The derived length and nilpotence class aren't difficult to calculate. What sort of things are you looking for?
Mar 15, 2015 at 18:08 history asked Igor Rivin CC BY-SA 3.0