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when toggle format what by license comment
Apr 10, 2015 at 0:05 answer added Robert Israel timeline score: 0
Mar 15, 2015 at 22:38 comment added Michele @Hurkyl. Hello, could you explain why this form is simpler?
Mar 14, 2015 at 19:46 comment added user13113 It may be simpler to write $sI = (sI-Q) + Q$ and use the alternative form $$ f(s) = w^T v + (w^T Q) (sI-Q)^{-1} v $$
Mar 11, 2015 at 23:28 comment added user13113 I'm not sure if it helps, but if we consider diagonal $Q$ (e.g. if we diagonalize), then $\lim_{s \to 0} s(sI-Q)^{-1}$ sends the zero diagonal entries to $1$ and the nonzero diagonal entries to $0$.
Mar 10, 2015 at 21:58 answer added Alex Degtyarev timeline score: 1
Mar 10, 2015 at 21:37 history asked Michele CC BY-SA 3.0